Question

Среднее арифметическое двух чисел равно 72.найдите каждое число если одно из них на 4 меньше другого.)

Answer 1

Пусть x и y- неизвестные числа.Пусть x больше y на 4
Известно,что (x+y)/2=72 и x-y=4
Составим систему уравнений

(x+y)/2=72
x-y=4

x+y=144
x-y=4                                     x=4+y

4+y+y=144
2y=144-4
2y=140
y=140/2
y=70

x-y=4
x-70=4
x=4+70
x=74
Ответ:70 и 74

Answer 2

Finding the Two Numbers

To find the two numbers whose arithmetic mean is 72, with one number being 4 less than the other, we can set up the following equation:

Let's assume the larger number is x and the smaller number is y. According to the given information, we have:

1. The arithmetic mean of the two numbers is 72: - (x + y) / 2 = 72

2. One number is 4 less than the other: - x = y + 4

To solve this system of equations, we can substitute the value of x from the second equation into the first equation:

(x + y) / 2 = 72 ((y + 4) + y) / 2 = 72 (2y + 4) / 2 = 72 2y + 4 = 144 2y = 144 - 4 2y = 140 y = 140 / 2 y = 70

Now that we have the value of y, we can substitute it back into the second equation to find the value of x:

x = y + 4 x = 70 + 4 x = 74

Therefore, the two numbers are 70 and 74, with 70 being 4 less than 74.

Answer: The two numbers are 70 and 74, with 70 being 4 less than 74.