Question

Найти производную функции f(x) =5√x+3sin x -x3+4x

Answer 1

$f(x)=5\sqrt{x}+3sin(x)-x^3+4x \\ \\ f'(x)=(5\sqrt{x})'+(3sin(x))'-(x^3)'+(4x)'= \\ \\ =(5(x)^{\frac{1}{2}})'+(3sin(x))'-(x^3)'+(4x)'= \\ \\ =5*\frac{1}{2}*x^{(\frac{1}{2}-1)}+3*cos(x)-3*x^{3-1}+4*x^{1-1}= \\ \\ =\frac{5}{2}*x^{(-\frac{1}{2})}+3cos(x)-3x^{2}+4x^{0}= \\ \\ =\frac{5}{2}*(\frac{1}{x})^{(\frac{1}{2})}+3cos(x)-3x^{2}+4=\frac{5}{2\sqrt{x}}+3cos(x)-3x^{2}+4$