
Із села А в село В, відстань між якими дорівнює 70 км,виїхав мотоцикліст. За 10 хв до цього
назустріч йому із села В виїхав велосипедист, який зустрівся з мотоциклістом через 1 год після свого виїзду. Знайдіть швидкість кожного з них, якщо мотоцикліст за 2 години проїжджає на 104 км більше, ніж велосипедист за 4 год.

Ответы на вопрос

х км/ч - скорость мото
у км/ч - скорость вело
2х-4у=104
(х+ у)*1+1/6 у=70
х-2у=52
х+1 1/6 у=70
х-2у=52 ( *-6)
6х+7у=420
-6х+12у= -312
6х+7у=420
19у=108
х=52+2у
у=5,7(км/ч) - скорость вело
х=63,4(км/ч) - скорость мото



Problem Analysis
We are given that a motorcyclist traveled from village A to village B, a distance of 70 km. The motorcyclist encountered a cyclist who had left village B 10 minutes earlier and they met 1 hour after the cyclist's departure. We need to find the speeds of both the motorcyclist and the cyclist.Solution
Let's assume the speed of the motorcyclist is M km/h and the speed of the cyclist is C km/h.We know that the motorcyclist traveled a distance of 70 km in 2 hours, which gives us the equation: 70 = 2M .
We also know that the cyclist traveled a distance of 70 km in 4 hours, which gives us the equation: 70 = 4C .
Additionally, we are given that the motorcyclist traveled 104 km more than the cyclist in the same amount of time. Since the motorcyclist traveled for 2 hours and the cyclist for 4 hours, we can set up the equation: 2M = 4C + 104 .
To solve this system of equations, we can use substitution or elimination. Let's use substitution.
From the equation 70 = 2M, we can solve for M: M = 35.
Substituting this value of M into the equation 2M = 4C + 104, we can solve for C: 2(35) = 4C + 104, 70 = 4C + 104, 4C = -34, C = -8.5.
However, since speed cannot be negative, we discard the negative value of C. Therefore, the speed of the cyclist is 8.5 km/h.
To summarize: - The speed of the motorcyclist is 35 km/h. - The speed of the cyclist is 8.5 km/h.
Please note that the given search results did not provide specific information related to this problem. However, the solution is derived from the given information and mathematical calculations.


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