Question

Ширина пямоугольника 4 см длина на2 см больше вычисли периметр и площадь прямоугольника

Answer 1

$AB=CD=4cm \\ AD=BC=4cm+2cm=6cm \\ \\ P_{ABCD}=2*4+2*6=8+12=20 \\ P_{ABCD}=20cm \\ \\ S_{ABCD}=AB*AD=4*6=24 \\ S_{ABCD}=24cm^2$

Answer 2

Ш-4см  д-4+2=6см  P-(4+6)x2=20cv  S-4x6=24кв см

Answer 3

Calculation of Perimeter and Area of a Rectangle

To calculate the perimeter and area of a rectangle, we need to know the width and length of the rectangle. In this case, the width of the rectangle is 4 cm, and the length is 2 cm more than the width.

Let's calculate the perimeter and area of the rectangle step by step:

Step 1: Calculate the length of the rectangle The length of the rectangle is 2 cm more than the width, which means it is 4 cm + 2 cm = 6 cm.

Step 2: Calculate the perimeter of the rectangle The perimeter of a rectangle is the sum of all its sides. In this case, the rectangle has two sides of width 4 cm and two sides of length 6 cm.

Perimeter = 2 * (Width + Length) Perimeter = 2 * (4 cm + 6 cm) Perimeter = 2 * 10 cm Perimeter = 20 cm

Therefore, the perimeter of the rectangle is 20 cm.

Step 3: Calculate the area of the rectangle The area of a rectangle is calculated by multiplying its length by its width.

Area = Length * Width Area = 6 cm * 4 cm Area = 24 cm^2

Therefore, the area of the rectangle is 24 cm^2.

To summarize: - The perimeter of the rectangle is 20 cm. - The area of the rectangle is 24 cm^2.