Question

Сколькими нулями заканчивается произвидение натуральных чисел от 1 до 25 включительно?

Answer 1

0 дают 10 20 и 5 в конце умноженное на четное число 
10 20 5и2 15и12 25и4(два) итого 6

Answer 2

Произведение натуральных чисел от 1 до 25 включительно заканчивается 6 нулями.

To find the number of trailing zeros in the product of natural numbers from 1 to 25, we need to determine the number of factors of 10 in the product. Since 10 can be expressed as 2 * 5, we need to count the number of factors of 2 and 5 in the product.

The number of factors of 2 will always be greater than or equal to the number of factors of 5. Therefore, we only need to count the number of factors of 5.

To find the number of factors of 5 in the product, we can divide each number from 1 to 25 by 5 and count the number of multiples of 5. However, we also need to consider numbers that are multiples of 25, as they contribute an additional factor of 5.

Let's calculate the number of factors of 5 in the product:

- Numbers that are multiples of 5: 5, 10, 15, 20, 25 (5 numbers) - Numbers that are multiples of 25: 25 (1 number)

Therefore, there are a total of 5 + 1 = 6 factors of 5 in the product.

Since each factor of 5 contributes a trailing zero, the product of natural numbers from 1 to 25 will have 6 trailing zeros.

(www.wolframalpha.com)