Question

В забеге присутствовали заяц и черепаха. Заяц бежит в 35 раз быстрей чем черепах. Черепаха преодолела всю дистанцию за 2 часа и 20 минут. Как долго спал заяц если известно что они финишировали одновременно

Answer 1

Пусть х скорость черепахи
тогда х*35 скорость зайца
l=x*140min (расстояние)
t=x*140min/(x*35)=4min (время зайца)
140-4=136min=2ч16мин
Ответ: заяц спал 2ч 16мин

Answer 2

Problem Analysis

In this problem, we are given that a hare and a tortoise participated in a race. The hare runs 35 times faster than the tortoise. The tortoise completes the entire distance in 2 hours and 20 minutes. We need to determine how long the hare slept if they finished the race at the same time.

Solution

Let's assume that the distance of the race is d.

The tortoise completes the race in 2 hours and 20 minutes, which is equivalent to 2.33 hours. Since the hare runs 35 times faster than the tortoise, it would take the hare 2.33 / 35 hours to complete the race.

To find out how long the hare slept, we need to subtract the time it took for the hare to complete the race from the total time taken by the tortoise.

Let's calculate the time taken by the hare to complete the race:

Time taken by the hare = (Time taken by the tortoise) / (Speed ratio)

Time taken by the hare = 2.33 / 35 hours

Now, let's calculate the time the hare slept:

Time the hare slept = (Time taken by the tortoise) - (Time taken by the hare)

Substituting the values:

Time the hare slept = 2.33 - (2.33 / 35) hours

Calculating the result:

Time the hare slept = 2.33 - 0.0666 hours

Time the hare slept = 2.2634 hours

Therefore, the hare slept for approximately 2.2634 hours.

Answer

The hare slept for approximately 2.2634 hours.