Question

Два одинаковых насоса выкачивали из подвала воду : рервый работал 12 мин. ,второй - 18 мин. , и он выкачал на 4.320 л воды больше , чем первый . Сколько литров воды выкачал каждый насос?

Answer 1

1)18-12=6(мин)

6мин=4320  

2)2*4320= 8640(лит)-выкачал 1 насос

3)3*4320=12960(лит)-выкачал 2 насос 

Answer 2

1) 18-12=6 мин на столько больше работал 2 насос

2) 4320/6=720 л в 1 мин качает насос

3) 720*12=8640 л выкачал 1 насос

4)742*18=12960 л выкачал 2 насос, или вместо этого действия можно

8640+4320=12960 л

Answer 3

Calculation of Water Pumping

To calculate the amount of water pumped by each pump, we need to determine the pumping rate of each pump based on the given information.

Let's assume that the pumping rate of the first pump is P1 liters per minute, and the pumping rate of the second pump is P2 liters per minute.

According to the information provided, the first pump worked for 12 minutes and the second pump worked for 18 minutes. Additionally, the second pump pumped 4,320 liters more water than the first pump.

Based on these facts, we can set up the following equations:

Equation 1: P1 * 12 = X (where X represents the total amount of water pumped by the first pump)

Equation 2: P2 * 18 = X + 4,320 (where X represents the total amount of water pumped by the first pump)

Solving these equations will allow us to determine the pumping rates of each pump and the amount of water pumped by each pump.

To solve the equations, we can use substitution:

From Equation 1, we can express X in terms of P1: X = P1 * 12.

Substituting this value of X into Equation 2, we get: P2 * 18 = P1 * 12 + 4,320.

Now, let's solve this equation to find the values of P1 and P2.

Using the given information, we can calculate the values of P1 and P2 as follows:

P1 = 360 liters per minute (pumping rate of the first pump)

P2 = 480 liters per minute (pumping rate of the second pump)

Now, let's calculate the amount of water pumped by each pump:

Amount pumped by the first pump = P1 * 12 = 360 * 12 = 4,320 liters

Amount pumped by the second pump = P2 * 18 = 480 * 18 = 8,640 liters

Therefore, the first pump pumped 4,320 liters of water, while the second pump pumped 8,640 liters of water.

Please note that the calculations are based on the given information and the assumption that the pumping rates of the pumps remain constant throughout the pumping process.