Question

От одной пристани отошли одновременно две моторные лодки в противоположных направлениях . Одна шла со скоростью 250м/мин,а другая- 200 м/мин. На каком расстоянии друг от друга будут лодки через 40 мин? Составь и реши обратную задачупомогите плиз

Answer 1

1.250+200=450(М/Мин)- скорость удаления

2.450*40=18000(М/Мин)-расстояние через 40 минут

Обратная задача:

1.250+200=450(М/мин)-скорость удаления

2.18000/450=40(мин)-лодки встретятся

 

 

 

 :)))))))))))))

 

 

 

 

 

 

Answer 2

(250+200)*40=450*40=18000м 

18000м=18км

Ответ 18 км

Тыкай лучшее решение))и лайк =D 

 

Answer 3

Problem Analysis

We have two motorboats that start from the same dock and move in opposite directions. One boat has a speed of 250 m/min, while the other boat has a speed of 200 m/min. We need to find the distance between the two boats after 40 minutes.

Solution

To solve this problem, we can use the formula: distance = speed × time.

Let's calculate the distance each boat travels in 40 minutes:

- Boat 1: distance = speed × time = 250 m/min × 40 min = 10,000 m - Boat 2: distance = speed × time = 200 m/min × 40 min = 8,000 m

Now, let's find the distance between the two boats. Since they are moving in opposite directions, we can add the distances:

- Total distance = distance of Boat 1 + distance of Boat 2 = 10,000 m + 8,000 m = 18,000 m

Therefore, the two boats will be 18,000 meters apart after 40 minutes.

Backward Problem

Now, let's solve the backward problem. Given that the two boats are 18,000 meters apart, we need to find the time it takes for them to reach this distance.

To find the time, we can rearrange the formula: time = distance / speed.

Let's calculate the time it takes for each boat to reach 18,000 meters:

- Boat 1: time = distance / speed = 18,000 m / 250 m/min = 72 minutes - Boat 2: time = distance / speed = 18,000 m / 200 m/min = 90 minutes

Therefore, it will take Boat 1 72 minutes and Boat 2 90 minutes to be 18,000 meters apart.

I hope this helps! Let me know if you have any further questions.