Question

Два сомолёта летели с одинаковой скоростью. Один самолёт был в воздухе 4 ч,другой -6ч.Первый сомолёт пролетел меньше второго на 1400км. какое расстояние пролетел каждый сомолёт?ПОЖАЛУЙСТА ТОЛЬКО БЫСТРО

Answer 1

6-4=2
1400:2=700
700*4=2800
700*6=4200

Answer 2

Problem Analysis

We are given two airplanes flying at the same speed. One airplane is in the air for 4 hours, while the other is in the air for 6 hours. The first airplane flies 1400 km less than the second airplane. We need to find the distance traveled by each airplane.

Solution

Let's assume the speed of both airplanes is x km/h.

The distance traveled by the first airplane can be calculated as 4x km (since it is in the air for 4 hours).

The distance traveled by the second airplane can be calculated as 6x km (since it is in the air for 6 hours).

According to the problem, the first airplane traveled 1400 km less than the second airplane. Therefore, we can set up the following equation:

4x = 6x - 1400

Simplifying the equation, we get:

2x = 1400

Solving for x, we find:

x = 700

Now, we can calculate the distance traveled by each airplane:

- The first airplane traveled 4x = 4 * 700 = 2800 km. - The second airplane traveled 6x = 6 * 700 = 4200 km.

Therefore, the first airplane traveled 2800 km, and the second airplane traveled 4200 km.

Answer

The first airplane traveled a distance of 2800 km, and the second airplane traveled a distance of 4200 km.