Question

Два велосипедиста выехали одновременно навстречу друг другу из двух поселков, расстояние между которыми 76 км. Через 2 ч они встретились. Какова скорость каждого велосипедиста, если известно что скорость одного на 3,5 км/ч меньше, чем другого?Ребята очень срочно надо, пожалуйста помогите!!!!

Answer 1

Пусть скорость первого - x (км/ч), тогда второго - 1,5*x (км/ч)1) x+1,5x=2,5x (км/ч) - скорость сближения2) 2,5x*2=765x=76x=76/5x=15,2 (км/ч) - скорость первого15,2*1,5=22,8 (км/ч) - скорость второгоОтвет: 15,2км/ч и 22,8км/ч

Answer 2

Problem Analysis

We have two cyclists who start simultaneously from two different towns and meet after 2 hours. The distance between the towns is 76 km. We are given that one cyclist's speed is 3.5 km/h less than the other cyclist's speed. We need to find the speed of each cyclist.

Solution

Let's assume the speed of the faster cyclist is x km/h. Then the speed of the slower cyclist will be x - 3.5 km/h.

We can use the formula: speed = distance / time to find the speeds of the cyclists.

The faster cyclist travels a distance of 76 km in 2 hours, so their speed is 76 / 2 = 38 km/h.

The slower cyclist's speed is 3.5 km/h less than the faster cyclist's speed, so their speed is 38 - 3.5 = 34.5 km/h.

Therefore, the speed of the faster cyclist is 38 km/h and the speed of the slower cyclist is 34.5 km/h.

Answer

The speed of the faster cyclist is 38 km/h and the speed of the slower cyclist is 34.5 km/h.

Note: The sources provided did not contain the exact solution to the problem. The solution was derived using basic mathematical principles.