
Помагите пожалуйста решать задачи. В соревнованиях по плованию участвовали 8 команд мальчиков , по
7 мальчиков каждой, и ещё 21 девочка. на сколько девочек меньше, чем мальчиков? сколько всего детей участвовал в соревнованиях?

Ответы на вопрос

56+21=77
56-21=35






Problem Analysis
We are given that 8 teams of boys participated in a swimming competition, with 7 boys in each team. Additionally, there were 21 girls participating. We need to determine the difference between the number of girls and boys, as well as the total number of children participating in the competition.
Solution
To find the difference between the number of girls and boys, we need to calculate the total number of boys and subtract the number of girls.
The total number of boys can be calculated by multiplying the number of teams by the number of boys in each team:
Total number of boys = Number of teams * Number of boys in each team
Let's calculate the total number of boys:
Total number of boys = 8 * 7 = 56
Now, we can find the difference between the number of girls and boys:
Difference = Number of girls - Total number of boys
Substituting the given values:
Difference = 21 - 56
Simplifying the expression:
Difference = -35
Therefore, there are 35 fewer girls than boys in the competition.
To calculate the total number of children participating in the competition, we need to add the number of boys and girls:
Total number of children = Total number of boys + Number of girls
Substituting the given values:
Total number of children = 56 + 21
Simplifying the expression:
Total number of children = 77
Therefore, a total of 77 children participated in the swimming competition.
Answer
There are 35 fewer girls than boys in the competition, and a total of 77 children participated in the swimming competition.


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