Question

Вычислите площадь основания прямоугольного параллелепипеда по данному объёму V и высоту Н. 1)V=340,6 дм³;Н=6,5 дм; 2)V=638,88 м³;Н=8,8 м. Пожалуйста срочно надо!!!(с понятным объяснением, а то иногда не доходит))))

Answer 1

Площадь основания S :
s=v:h
1) s=340,6:6,5=52,4 дм квадратных
2) s=638,88:8,8=72,6 м квадратных

Answer 2

Calculating the Area of the Base of a Rectangular Parallelepiped

To calculate the area of the base of a rectangular parallelepiped (a three-dimensional figure with six faces, each of which is a parallelogram), we can use the formula:

Area of the base = Volume / Height

Let's calculate the area of the base for the given volumes and heights.

1. For V = 340.6 dm³ and H = 6.5 dm: - Using the formula, the area of the base is calculated as: ``` Area = Volume / Height Area = 340.6 dm³ / 6.5 dm Area ≈ 52.4 dm² ```

The area of the base for the first set of values is approximately 52.4 dm².

2. For V = 638.88 m³ and H = 8.8 m: - Using the formula, the area of the base is calculated as: ``` Area = Volume / Height Area = 638.88 m³ / 8.8 m Area ≈ 72.6 m² ```

The area of the base for the second set of values is approximately 72.6 m².

In summary, the area of the base for the given volumes and heights is approximately 52.4 dm² and 72.6 m², respectively.

I hope this explanation helps! If you have further questions or need additional assistance, feel free to ask.