Question

За 8 часов 1 мастерсделал 240 деталей Другой за это же время -320 деталей за какое время мастера сделают 280 деятелей работая вместе???

Answer 1

240/8 = 30дет/ч скорость первого
320/8= 40 дет/ч скорость второго
 280/(30+40) = 4 часа им потребуется

Answer 2

Problem Analysis

We have two masters who are working together. One master can make 240 parts in 8 hours, while the other master can make 320 parts in the same time. We need to determine how long it will take for the two masters to make 280 parts working together.

Solution

To solve this problem, we can calculate the combined efficiency of the two masters and then use it to determine the time required to make 280 parts.

Let's calculate the efficiency of each master first:

- Master 1: 240 parts in 8 hours - Master 2: 320 parts in 8 hours

The efficiency of each master can be calculated by dividing the number of parts produced by the number of hours worked:

- Efficiency of Master 1: 240 parts / 8 hours = 30 parts per hour - Efficiency of Master 2: 320 parts / 8 hours = 40 parts per hour

Now, let's calculate the combined efficiency of the two masters by adding their individual efficiencies:

- Combined efficiency = Efficiency of Master 1 + Efficiency of Master 2 = 30 parts per hour + 40 parts per hour = 70 parts per hour

Finally, we can determine the time required to make 280 parts by dividing the total number of parts by the combined efficiency:

- Time required = Total number of parts / Combined efficiency = 280 parts / 70 parts per hour = 4 hours

Therefore, it will take the two masters working together 4 hours to make 280 parts.

Answer

The two masters will take 4 hours to make 280 parts working together.