Question

РАЗЛОЖИТЕ МНОГЧЛЕН 8t''' + 1 на множители

Answer 1

8t + 1=(2t^2+1)(2t +1)

Думаю, что так

Answer 2

Хотя нет((((ихвени..я не знаю как

Answer 3

Factoring the Polynomial 8t''' + 1

To factor the polynomial 8t''' + 1, we can start by looking for common factors. In this case, there are no common factors other than 1. So, we need to use other methods to factorize the polynomial.

One approach is to use the fact that if a polynomial has a root, then (t - root) is a factor of the polynomial. So, let's try to find a root of the polynomial 8t''' + 1.

To find the root, we can set the polynomial equal to zero and solve for t:

8t''' + 1 = 0

Subtracting 1 from both sides:

8t''' = -1

Dividing both sides by 8:

t''' = -1/8

Therefore, t = -1/2 is a root of the polynomial.

Now that we have found a root, we can use synthetic division or long division to divide the polynomial by (t - (-1/2)) = (t + 1/2). However, since the polynomial has a degree of 3, we can use synthetic division for simplicity.

Performing synthetic division with t = -1/2:

   -1/2   |   8    0    0    1
          |  -4    2   -1
          |_________________
            8   -4    2    0

The result of the synthetic division is 8t^2 - 4t + 2. This is a quadratic polynomial.

Now, we can factor the quadratic polynomial 8t^2 - 4t + 2. However, after searching for relevant information, I couldn't find any specific factors for this quadratic polynomial.

Therefore, the factored form of the polynomial 8t''' + 1 is:

8t''' + 1 = (t + 1/2)(8t^2 - 4t + 2)

Please note that the quadratic polynomial 8t^2 - 4t + 2 may not have any further factorization using real numbers.