Question

Катер и моторная лодка одновременно отошли от одной пристани в противоположных направлениях. Средняя скорость катера 750м.мин. ,а средняя скорость моторной лодки на 250м.мин меньше. Какое расстояние будет междду ними через 2 часа?

Answer 1

1) 750 х 120 (2ч) = 90 000м за 2 часа пройдёт катер

2) 750 -250 = 500м/мин скорость лодки

3) 500 х 120 =60 000м за 2 часа пройдёт лодка

4) 90 000 + 60 000 =150 000м или 150км. буде расстояние через 2 часа между катером и лодкой

Answer 2

Problem Analysis

We are given that a boat and a motorboat leave a dock at the same time in opposite directions. The average speed of the boat is 750 m/min, while the average speed of the motorboat is 250 m/min less than the boat's speed. We need to find the distance between them after 2 hours.

Calculation

To find the distance between the boat and the motorboat after 2 hours, we need to calculate the total distance traveled by each of them.

The boat's average speed is 750 m/min, so in 2 hours (120 minutes), it would travel a distance of 750 m/min * 120 min = 90,000 meters.

The motorboat's average speed is 250 m/min less than the boat's speed, so its speed is 750 m/min - 250 m/min = 500 m/min. In 2 hours (120 minutes), the motorboat would travel a distance of 500 m/min * 120 min = 60,000 meters.

The distance between them after 2 hours would be the sum of the distances traveled by each of them. Therefore, the distance between them would be 90,000 meters + 60,000 meters = 150,000 meters.

Answer

The distance between the boat and the motorboat after 2 hours would be 150,000 meters.