Question

Две морские звезды одновременно поползли навстречу друг другу из своих укрытий , расстояние между которыми 27 дм , и встретились через 3ч. С какой скоростью ползла первая звезда, если она двигалась на 1 дм/ч быстрее второй

Answer 1

Скорость сближения морских звёзд равна 27:3=9дм/ч
скорость одной из медуз равна х
скорость второй медузы будет равна х+1
х+х+1=9
2х=8
х=4дм/ч
х+1=5дм/ч - скорость второй медузы

Answer 2

Problem Analysis

We are given that two sea stars simultaneously crawled towards each other from their hiding places, and the distance between them was 27 dm. They met after 3 hours. We need to determine the speed at which the first sea star crawled, given that it moved 1 dm/h faster than the second sea star.

Solution

Let's assume the speed of the second sea star is x dm/h. Since the first sea star moves 1 dm/h faster, its speed will be (x + 1) dm/h.

We can use the formula distance = speed × time to calculate the distance traveled by each sea star.

For the first sea star: - Speed = (x + 1) dm/h - Time = 3 hours - Distance = ?

For the second sea star: - Speed = x dm/h - Time = 3 hours - Distance = ?

Since the two sea stars are crawling towards each other, the sum of their distances should be equal to the total distance between them, which is 27 dm.

We can set up the following equation to solve for the distances: (x + 1) × 3 + x × 3 = 27

Simplifying the equation: 3x + 3 + 3x = 27 6x + 3 = 27 6x = 24 x = 4

Therefore, the speed of the second sea star is 4 dm/h. Since the first sea star moves 1 dm/h faster, its speed is (4 + 1) = 5 dm/h.

Answer

The first sea star crawled at a speed of 5 dm/h.