Question

Две артели рабочих получили вместе 828 рублей.Сколько человек было в каждой артели,если вторая артель получила вдвое больше денег,чем первая,и,кроме того,рабочие первой артели получили по 12 рублей,а второй- по 8 рублей? СРОЧНО!!!

Answer 1

Х - получила первая артель
2х - получила вторая
х+2х=828
3х=828
х=828:3
х=276 (р) получила первая
276*2=552 (р) вторая
276:12=23 (чел) в первой
552:8=69 (чел) во второй
Ответ: в первой артели 23 человека, во второй 69 человек

Answer 2

Х - вторая артель, значит
2х - первая артель

х + 2х = 828
3х = 828
х = 276 (руб) - получила вторая артель
276 * 2 = 552 (руб) - получила первая артель

276 : 12 = 23 рабочих в первой артели
552 : 8 = 69 рабочих во второй артели

ОТВЕТ: в первой артели 23 рабочих, а во второй артели 69 рабочих. 

Answer 3

Problem Analysis

We are given that two groups of workers received a total of 828 rubles. The second group received twice as much money as the first group. Additionally, the workers in the first group received 12 rubles each, while the workers in the second group received 8 rubles each. We need to determine the number of workers in each group.

Solution

Let's assume that the number of workers in the first group is x. Since each worker in the first group received 12 rubles, the total amount of money received by the first group can be calculated as 12x.

According to the problem, the second group received twice as much money as the first group. Therefore, the total amount of money received by the second group is 2 * 12x = 24x.

The total amount of money received by both groups is given as 828 rubles. So we can write the equation:

12x + 24x = 828

Simplifying the equation:

36x = 828

Now we can solve for x:

x = 828 / 36 = 23

Therefore, there were 23 workers in the first group.

To find the number of workers in the second group, we can substitute the value of x into the equation:

y = 2x = 2 * 23 = 46

Therefore, there were 46 workers in the second group.

Answer

There were 23 workers in the first group and 46 workers in the second group.