Question

Решение задачи периметр пола спортивного зала 80 м найдите объём зала если его длина в 3 раза больше ширины а высота равна 4 м 5 дм

Answer 1

Пусть ширина х м, тогда длина 3х м
Р=2(х+3х)
80 = 2(х+3х)
80=2*4х
80=8х
х=10 м (100 дм) ширина
10*3 = 30 м   (300 дм) длина
V=а*в*с = 100*300*45 = 1 350 000 дм³ = 1 350 м³

Answer 2

Calculating the Volume of a Sports Hall

To find the volume of the sports hall, we first need to calculate the dimensions of the hall based on the given information.

Given: - Perimeter of the sports hall = 80 m - Length is 3 times the width - Height = 4 m 5 dm

Calculating the Dimensions of the Sports Hall

Let's denote: - Length as L - Width as W - Height as H

From the given information, we can form the following equations: 1. Perimeter = 2(L + W) = 80 m 2. L = 3W 3. H = 4 m 5 dm = 4.5 m

We can use these equations to find the values of L and W.

Calculating Length and Width

From equation (2), L = 3W. We can substitute this value of L in equation (1) to solve for W.

2(3W + W) = 80 2(4W) = 80 8W = 80 W = 10 m

Now that we have the value of W, we can find the value of L using L = 3W.

L = 3 * 10 L = 30 m

So, the length of the sports hall (L) is 30 m and the width (W) is 10 m.

Calculating the Volume

Now that we have the dimensions of the sports hall, we can calculate its volume using the formula:

Volume = Length × Width × Height

Substituting the given values: Volume = 30 m × 10 m × 4.5 m Volume = 1350 cubic meters

Therefore, the volume of the sports hall is 1350 cubic meters.