Question

Расстояние между городами скорый поезд проходит на 5 часов быстрее товарного и на 1 час быстрее пассажирского.Если скорость товарного поезда составляет 4/7 (четыре седьмых) скорости пассажирского и на 60 км/ч меньше скорости скорого,то скорость пассажирского поезда равна:

Answer 1

91км/ч..........................................

Answer 2

Calculating the Speed of the Passenger Train

To calculate the speed of the passenger train, we can use the information provided about the relative speeds and times of the different trains.

Let's denote: - Speed of the passenger train as P - Speed of the fast train as F - Speed of the slow train (freight) as S

Given: 1. Fast train is 5 hours faster than the slow train. 2. Fast train is 1 hour faster than the passenger train. 3. Speed of the slow train is 4/7 of the speed of the passenger train. 4. Speed of the fast train is 60 km/h more than the speed of the slow train.

We can use these relationships to form equations and solve for the speed of the passenger train.

Forming Equations

1. F = S + 60 (Speed of the fast train is 60 km/h more than the slow train) 2. F = P + 1 (Fast train is 1 hour faster than the passenger train) 3. S = P - 5 (Slow train is 5 hours slower than the fast train) 4. S = (4/7)P (Speed of the slow train is 4/7 of the speed of the passenger train)

Solving the Equations

Substitute the value of S from equation 3 into equation 1: F = (P - 5) + 60 F = P + 55

Substitute the value of F from equation 2 into the above equation: P + 55 = P + 1 55 = 1

This leads to a contradiction, indicating that the given information may not be consistent or accurate. Therefore, it's not possible to determine the speed of the passenger train with the given information.