Question

Из двух городов, расстояние между которыми 7400км,вылетели одновременно навстречу друг другу два самолета и встретились через 4часа.Скорость одного самолета 950км/ч.Определи скорость второго самолета?

Answer 1

1) 7400:4=1850 км/ч скорось сближения самолетов
2) 1850-950 = 900 км/ч скорость второго самолёта

Ответ: скорость второго самолета 900 км/ч

Answer 2

Problem Analysis

We have two cities that are 7400 km apart. Two planes took off simultaneously from these cities and met each other after 4 hours. The speed of one plane is given as 950 km/h. We need to determine the speed of the second plane.

Solution

Let's assume the speed of the second plane is x km/h.

Since both planes are flying towards each other, their combined speed is equal to the sum of their individual speeds. Therefore, the combined speed of the two planes is 950 km/h + x km/h.

We can use the formula distance = speed × time to calculate the distance traveled by each plane.

For the first plane: - Speed = 950 km/h - Time = 4 hours - Distance = 950 km/h × 4 hours = 3800 km

For the second plane: - Speed = x km/h - Time = 4 hours - Distance = x km/h × 4 hours = 4x km

Since the total distance traveled by both planes is equal to the distance between the two cities (7400 km), we can set up the following equation:

3800 km + 4x km = 7400 km

Now, we can solve this equation to find the value of x.

3800 km + 4x km = 7400 km

Subtracting 3800 km from both sides:

4x km = 7400 km - 3800 km

4x km = 3600 km

Dividing both sides by 4:

x km = 3600 km / 4

x km = 900 km/h

Therefore, the speed of the second plane is 900 km/h.

Answer

The speed of the second plane is 900 km/h.