Question

Периметр прямоугольника равен 76 см.Найди его площадь,если ширина меньше длины на 4 см. Пжалуйста пишите без уравнений

Answer 1

76:2=38см сумма длины и ширины   
(38-4):2=17см ширина
17+4=21см длина
S=17*21=357см2 площадь 

Answer 2

Finding the Area of a Rectangle with Given Perimeter

To find the area of a rectangle when the perimeter is given, we need to know the length and width of the rectangle. In this case, we are given that the perimeter of the rectangle is 76 cm, and the width is 4 cm less than the length.

Let's denote the length of the rectangle as L and the width as W. We can set up the following equations based on the given information:

1. Perimeter of a rectangle: 2L + 2W = 76. 2. Width is 4 cm less than the length: W = L - 4.

To find the area of the rectangle, we need to multiply the length by the width: Area = L * W.

Solving for Length and Width

Let's solve the equations to find the values of length and width.

From equation 2, we can substitute the value of W in equation 1:

2L + 2(L - 4) = 76

Simplifying the equation:

2L + 2L - 8 = 76

4L - 8 = 76

4L = 84

L = 21

Now that we have the value of L, we can substitute it back into equation 2 to find the value of W:

W = L - 4 = 21 - 4 = 17

Therefore, the length of the rectangle is 21 cm and the width is 17 cm.

Finding the Area

Now that we have the length and width of the rectangle, we can find the area by multiplying them:

Area = Length * Width = 21 cm * 17 cm = 357 cm²

Therefore, the area of the rectangle is 357 cm².

Please let me know if there's anything else I can help you with!