Question

В первом баке воды в 3 раза меньше, чем во втором. В первый бак долили 5 л воды, а из второго вылили 7 л, после чего воды в баках стало поровну.Сколько литров воды было в каждем баке?Составте уравнение ,соответсвующие условию задачи,если х обозначало количество воды в 1 баке

Answer 1

Пусть х л воды было в 1 баке.
Тогда 3х л воды было во 2 баке.
(х+5) л воды - стало в 1 баке.
(3х-7) л воды - стало во 2 баке.
По усл. задачи изв-но, что воды в баках стало поровну.
Сост. ур-ние:
х+5=3х-7
2х=12
х=6
6 л воды было в 1 баке.
3*6=18 л воды было во 2 баке.

Answer 2

1 бак-х
2 бак-3х
х+5=3х-7
х-3х=-5-7
-2х=-12
х=-12:(-2)
х=6 литров было в 1 баке
6*3=18 литров было во 2 баке

Answer 3

Problem Analysis

We are given two tanks, and the amount of water in the first tank is three times less than the amount of water in the second tank. We are also given that 5 liters of water are poured into the first tank and 7 liters of water are poured out of the second tank. After these operations, the amount of water in both tanks is equal. We need to find the amount of water in each tank.

Let's denote the amount of water in the first tank as 'x' liters.

Formulating the Equation

According to the problem, the amount of water in the first tank is three times less than the amount of water in the second tank. This can be expressed as:

Amount of water in the first tank = Amount of water in the second tank - 3 * Amount of water in the first tank

Using the variable 'x' to represent the amount of water in the first tank, we can write the equation as:

x = (3x + 7) - 5

Simplifying the equation:

x = 3x + 7 - 5

x = 3x + 2

Subtracting 'x' from both sides:

0 = 2x + 2

Subtracting 2 from both sides:

-2 = 2x

Dividing both sides by 2:

-1 = x

Therefore, the amount of water in the first tank is -1 liter.

Answer

Based on the equation, the amount of water in the first tank is -1 liter. However, it is not possible to have a negative amount of water. Therefore, there is no valid solution to this problem.

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