Question

Задумали два числа их сумма равна 48 а частное ровно 7 какие это числа

Answer 1

Первое число Х
Второе число ( 48 - Х )
Х : ( 48 - Х ) = 7
Х = 7( 48 - Х )
Х = 336 - 7х
8х = 336
Х = 42 ( первое число )
48 - 42 = 6 ( второе число )
Ответ 42 и 6

Answer 2

Задумаем число-х
2ч-(48-х)
Составим и решим задачу:
х:(48-х)=7
х=7•(48-х)
х=336-7х
8х=336
х=42- первое число
48-42=6-второе число
Ответ:42 и 6

Answer 3

Solution:

To find the two numbers, let's denote the numbers as x and y. We know that their sum is 48 and their quotient is 7. Therefore, we have the following equations:

1. Equation 1: x + y = 48 2. Equation 2: x / y = 7

Solving Equation 1:

We can solve Equation 1 for one of the variables and substitute it into Equation 2.

From Equation 1, we can express y in terms of x: y = 48 - x

Substituting into Equation 2:

Substituting y = 48 - x into Equation 2, we get: x / (48 - x) = 7

Solving for x:

Multiplying both sides by (48 - x), we get: x = 7(48 - x)

Expanding and solving for x: x = 336 - 7x 8x = 336 x = 42

Finding the second number:

Using the value of x, we can find y: y = 48 - x y = 48 - 42 y = 6

Therefore, the two numbers are 42 and 6.