Question

Угол MKD разделен лучом KP на два угла MKP и PKD. Угол MKP равен 21* градус и составляет три седьмых угла MKD. Найдите градусную меру углов MKD и PKD.

Answer 1

21 градус-три седьмых угла
x градусов-семь седьмых угла
x=21 умножить на семь седьмых и разделить на три седьмых. Значит,угол MKD=49 градусов. Угол PKD=угол MKD-угол MKP. PKD=49-21=28 градусов. Ответ:MKD-49 градусов,PKD-28 градусов.

Answer 2

Problem Analysis

We are given that angle MKP is equal to 21 degrees and is three sevenths of angle MKD. We need to find the degree measures of angles MKD and PKD.

Solution

Let's assume the degree measure of angle MKD is x degrees.

According to the given information, angle MKP is three sevenths of angle MKD. This can be expressed as:

MKP = (3/7) * MKD

We are also given that angle MKP is equal to 21 degrees. Substituting this value into the equation, we can solve for MKD:

21 = (3/7) * MKD

To find the degree measure of angle MKD, we can multiply both sides of the equation by (7/3):

MKD = 21 * (7/3)

Simplifying the expression, we get:

MKD = 49 degrees

Now, we can find the degree measure of angle PKD. Since angle MKD is divided into two angles, MKP and PKD, we can subtract the degree measure of angle MKP from angle MKD to find the degree measure of angle PKD:

PKD = MKD - MKP

Substituting the values we found earlier:

PKD = 49 - 21

Simplifying the expression, we get:

PKD = 28 degrees

Therefore, the degree measure of angle MKD is 49 degrees and the degree measure of angle PKD is 28 degrees.

Answer

The degree measure of angle MKD is 49 degrees and the degree measure of angle PKD is 28 degrees.