Question

Школьная футбольная команда выиграла в 3 раза больше игр, чем проиграла, а 4 игры закончила вничью. Всего было проведено 28 игр. Сколько игр выиграла команда?

Answer 1

28-4=24игры
24/4=6 игр проиграли
6*3=18 игр выиграли

Answer 2

28-4=24 проигрышей и побед
24:4=6 игр проиграли
6*3=18
Ответ:18

Answer 3

Calculating the Number of Wins for the School Football Team

To calculate the number of wins for the school football team, we can use the information provided in the question and the total number of games played.

Given Information: - Total games played: 28 - Wins: 3 times more than losses - Draws: 4 games ended in a draw

Let's calculate the number of wins for the team.

Calculation:

Let's denote: - Number of wins as W - Number of losses as L - Number of draws as D

We are given that the total games played is 28: - So, we have the equation: W + L + D = 28 It's also given that the team won 3 times more games than it lost: - This gives us the equation: W = 3L And 4 games ended in a draw: - So, we have the equation: D = 4 Using these equations, we can solve for the number of wins.

Solution:

From equation we can express L in terms of W: - L = W / 3

Substitute this into the equation W + L + D = 28: - W + (W / 3) + 4 = 28 - (4W + W + 12) / 3 = 28 - 5W + 12 = 84 - 5W = 72 - W = 72 / 5 - W = 14.4

Since the number of wins must be a whole number, we can conclude that the school football team won 14 games.

Therefore, the school football team won 14 games.

I hope this helps! If you have any other questions, feel free to ask.