Question

Из муравейника на поиски «строительного материала» в противоположных направлениях отправились два муравья. Скорость одного из них 5 см/сек. Через 30 сек расстояние между ними было 270 см. С какой скоростью перелвигаясь второй муравей

Answer 1

(270-5*30)/30=(270-150)/30=120/30=4см/сек

Answer 2

Calculation of the Second Ant's Speed

To determine the speed of the second ant, we can use the information provided in the question. We know that the first ant has a speed of 5 cm/sec and that after 30 seconds, the distance between the two ants is 270 cm.

Let's calculate the speed of the second ant:

1. We can start by calculating the total distance traveled by the first ant in 30 seconds. Since the speed of the first ant is 5 cm/sec, the total distance traveled by the first ant in 30 seconds is:

Distance = Speed × Time = 5 cm/sec × 30 sec = 150 cm

2. Since the distance between the two ants is 270 cm after 30 seconds, we can subtract the distance traveled by the first ant from the total distance to find the distance traveled by the second ant:

Distance traveled by the second ant = Total distance - Distance traveled by the first ant = 270 cm - 150 cm = 120 cm

3. Finally, we can calculate the speed of the second ant by dividing the distance traveled by the second ant by the time taken (30 seconds):

Speed of the second ant = Distance traveled by the second ant / Time = 120 cm / 30 sec = 4 cm/sec

Therefore, the second ant is moving at a speed of 4 cm/sec.

Please note that the sources provided did not contain specific information related to this question. The calculation is based on the given information and general mathematical principles.