Question

Два велосипедиста отправились из одного посёлка одновременно в противоположных направлениях. Через 30 мин расстояние между ними было 15 км. Узнай среднюю скорость другого велосипедиста.

Answer 1

допущено:Средняя скорость одного из них 260 м/мин.

 

15 км=15000 м

260*30=7800 м-------------проехал первый велосипедист за 30мин.

15000-7800=7200 м-------проехал второй велосипедист за 30мин.

7200:30=240м/мин-------средняя скорость второго велосипедиста.

Answer 2

1)260*30=7800м-проехал первый за 30мин.
2)15км(15000м)-7800м=7200м-проехал второй за 30мин.
3)7200:30=240м/мин-скорость второго-- среднюю скорость другого велосипедиста

Answer 3

Problem Analysis

Two cyclists start from the same village simultaneously in opposite directions. After 30 minutes, the distance between them is 15 km. We need to find the average speed of the other cyclist.

Solution

Let's assume the speed of the first cyclist is x km/h and the speed of the second cyclist is y km/h.

We know that the distance covered by the first cyclist in 30 minutes (0.5 hours) is 0.5x km, and the distance covered by the second cyclist in the same time is 0.5y km.

After 30 minutes, the distance between them is 15 km. This means that the sum of the distances covered by both cyclists is equal to 15 km:

0.5x + 0.5y = 15 To find the average speed of the second cyclist, we need to find the value of y.

Let's solve the equation:

0.5x + 0.5y = 15

Rearranging the equation:

0.5y = 15 - 0.5x

Multiplying both sides by 2 to eliminate the fraction:

y = 30 - x

So, the average speed of the second cyclist is 30 - x km/h.

Answer

The average speed of the second cyclist is 30 - x km/h.

Please note that we don't have the specific value of x (the speed of the first cyclist) to calculate the exact average speed of the second cyclist.