Question

X'4+25=26x'2 решите пожалуйста

Answer 1

Биквадратное ур-е

х↑2=у
тогда у↑2-26у+25=0
найдем корни , я - по теореме Виетта: 1) у=25  2) у=1 

(25+1=26, 25·1=25, ⇒верно)
тогда 1) х↑2=25 ⇒ 1.1 )х=5,      1.2) х= - 5
           2) х↑2=1 ⇒ 1.1 )х=1,       1.2) х= - 1

как-то вот так...-)))

           

Answer 2

Solving the Equation X^4 + 25 = 26x^2

To solve the equation X^4 + 25 = 26x^2, we can rearrange it to a standard form and then solve for the variable x.

First, let's subtract 26x^2 from both sides of the equation: X^4 - 26x^2 + 25 = 0

Now, we can treat this as a quadratic equation in terms of x^2. Let's substitute x^2 as a new variable, say y: y^2 - 26y + 25 = 0

We can then solve this quadratic equation for y using the quadratic formula: y = (-b ± √(b^2 - 4ac)) / (2a)

Where a = 1, b = -26, and c = 25.

After finding the values of y, we can then solve for x by taking the square root of the solutions for y.

Let's calculate the values of y and then solve for x.