Question

В кабинете математике в тех шкафах лежат модели геометрических фигур .Во втором шкафу на 4 модели больше , чем в третьем , и на 15 меньше чем в первом . Сколько моделей в каждом шкафу , если моделей всего 50 ?

Answer 1

(50-15-4*2)/3=9 моделей в 3-ем шкафу
9+4=13 моделей во 2-м шкафу
13+15=28 моделей в 1-м шкафу

Answer 2

Problem Analysis

We are given that there are three cabinets in a math classroom, and each cabinet contains a certain number of geometric figure models. The second cabinet has 4 more models than the third cabinet, and 15 fewer models than the first cabinet. We need to determine the number of models in each cabinet, given that there are a total of 50 models.

Solution

Let's assume the number of models in the third cabinet is x.

According to the given information: - The second cabinet has 4 more models than the third cabinet, so the number of models in the second cabinet is x + 4. - The second cabinet has 15 fewer models than the first cabinet, so the number of models in the first cabinet is x + 4 + 15 = x + 19.

The total number of models in all three cabinets is 50, so we can write the equation:

x + (x + 4) + (x + 19) = 50

Simplifying the equation: 3x + 23 = 50

Subtracting 23 from both sides: 3x = 27

Dividing both sides by 3: x = 9

Therefore, there are 9 models in the third cabinet, 9 + 4 = 13 models in the second cabinet, and 9 + 19 = 28 models in the first cabinet.

Answer

There are 9 models in the third cabinet, 13 models in the second cabinet, and 28 models in the first cabinet.