Question

Один мастер может выполнить задание за 2 дня, а другой мастер-за 3 дня.Какая часть задания останется невыполненной, если обамастера будут работать совместно один день?

Answer 1

Производительности их, соответственно 1/2 и 1/3.При совместной работе они за день выполнят:1/2   +   1/3  = 5/6  всего задания.Невыполненной останется: 1 -  5/6 = 1/6 часть задания.Ответ: 1/6.

Answer 2

Calculation of Task Completion

To determine the portion of the task that will remain unfinished if two masters work together for one day, we need to calculate their individual rates of completing the task.

Let's assume that the first master can complete the task in 2 days, and the second master can complete the task in 3 days.

The rate at which the first master completes the task is 1/2 of the task per day, while the rate at which the second master completes the task is 1/3 of the task per day.

When two masters work together, their rates of completing the task are additive. Therefore, the combined rate at which they complete the task is 1/2 + 1/3 of the task per day.

To find the portion of the task that remains unfinished after one day of working together, we subtract the combined rate from the total task:

1 - (1/2 + 1/3) = 1 - (3/6 + 2/6) = 1 - 5/6 = 1/6

Therefore, 1/6 of the task will remain unfinished if the two masters work together for one day.