Question

Дано: MKNR-ромб KR=10 MN=12 Все стoроны у этого ромба равны Найти: MK

Answer 1

Поскольку в ромба диагонали перисикаются под прямым углом то мы можем рассмотреть треугольник МОК (угол О прямой, это точка пересичения диагоналей) МО = $\frac{1}{2}$*MN=$\frac{1}{2}$*12=6
KO=$\frac{1}{2} *KR= \frac{1}{2} *10=5$
ну а теперь за т. Пифагора
MK²=MO²+KO²=6²+5²=36+25=61
MK=$\sqrt{61}$

Answer 2

Calculating the Length of MK in the Given Rhombus

To find the length of MK in the given rhombus, we can use the properties of a rhombus. In a rhombus, all sides are equal in length. Additionally, the diagonals of a rhombus bisect each other at right angles.

Given: - KR = 10 - MN = 12

We can use the Pythagorean theorem to find the length of MK. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Let's denote MK as x. Then, we can use the Pythagorean theorem to solve for x:

Using the Pythagorean Theorem: - KR^2 + MN^2 = MK^2 - 10^2 + 12^2 = MK^2 - 100 + 144 = MK^2 - 244 = MK^2 - MK = √244 - MK ≈ 15.62

So, the length of MK in the given rhombus is approximately 15.62.