Question

Среднее арифметическое двух чисел составляет 60% от большего из них. Во сколько раз среднее арифметическое этих чисел больше меньшего числа?

Answer 1

Х-меньшее число у-большее число; их среднее арифметическое-(х+у)/2  Составляем ур-ние;(х+у)/2=0,6у Решаем его относительно х: х+у=1,2у  х=0,2у Для ответа на вопрос задачи нужно разделить среднее арифметическое на меньшее число: (х+у)/2:х=(0,2у+у)/2:0,2у=0,6у/0,2у=3

Answer 2

Calculation of the Arithmetic Mean and Comparison with the Smaller Number

To find the arithmetic mean of two numbers and determine how many times the mean is greater than the smaller number, we need to set up an equation based on the given information.

Let's assume the two numbers are x and y, where x is the smaller number and y is the larger number.

According to the given information, the arithmetic mean of the two numbers is 60% of the larger number. Mathematically, this can be expressed as:

Mean = (60/100) * y

To find the ratio of the mean to the smaller number, we divide the mean by the smaller number:

Ratio = Mean / x

Substituting the value of the mean from the first equation, we get:

Ratio = [(60/100) * y] / x

Simplifying further, we have:

Ratio = (3/5) * (y / x)

Therefore, the ratio of the arithmetic mean to the smaller number is (3/5) * (y / x).

Please note that we don't have specific values for x and y, so we cannot calculate the exact ratio. However, we can provide the general formula for the ratio based on the given information.