Question

Заполни пропуски 3z+9000=15000 3z+9000 _ _ _ _ _ = 15000 _ _ _ _ _ 3z _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ __ _ _ __ _ __ _

Answer 1

3z+9000=15000
3z=15000-9000
3z=6000
z=6000÷3
z=2000
3×2000+9000=15000

Answer 2

3z + 9000 = 15000 To solve for z, we first subtract 9000 from both sides of the equation: 3z = 15000 - 9000 3z = 6000 Now, we divide both sides by 3 to isolate z: z = 6000 / 3 z = 2000

So, the missing values are: 3z + 9000 = 15000 3z + 9000 = 15000 3z + 9000 = 15000 3z + 2000 + 2000 + 2000 = 15000 3z + 6000 = 15000