Question

Длина полоски прямоугольной формы 10см,а ширина в 2 раза меньше,чем длина.Найди площадь и периметр полоски?

Answer 1

10/2 = 5см (ширинга)
P = (10+5)*2 = 30см - периметр
S = 10*5 = 50кв.см. - площадь

Answer 2

Если длина 10 см.а ширина в 2 раза меньше значит:
1)  10:2=5 Длина
2) 10*5=50 (S)Площадь!

Answer 3

Problem Analysis

We are given that the length of a rectangular strip is 10 cm and the width is 2 times smaller than the length. We need to find the area and perimeter of the strip.

Calculation

Let's calculate the width of the strip first. We are given that the width is 2 times smaller than the length, so the width would be 10 cm / 2 = 5 cm.

Now, we can calculate the area of the strip using the formula Area = length * width. Substituting the values, we get Area = 10 cm * 5 cm = 50 cm^2.

Next, let's calculate the perimeter of the strip using the formula Perimeter = 2 * (length + width). Substituting the values, we get Perimeter = 2 * (10 cm + 5 cm) = 2 * 15 cm = 30 cm.

Answer

Therefore, the area of the strip is 50 cm^2 and the perimeter of the strip is 30 cm.

Please let me know if you need any further assistance.