Question

В одном бассейне было 400 м воды в другом 600 м после того как во 2 басейне налили в 1.5 раза меньше воды чем в первый в первом воды стало на 100 М больше сколько воды налили в каждый басейн

Answer 1

Х м³ - налили во 2 бассейн
1,5м³ - налили в 1бассейн
400+1,5х-600+х=100
2,5х=300
х=300:2,5
х=120(м³) - налили во 2 бассейн
120*1,5=180(м³) - налили в 1 бассейн

Answer 2

Calculating the Water Added to Each Pool

To calculate the amount of water added to each pool, we can use the information provided and solve for the unknown quantities.

Let's denote: - x as the original amount of water in the first pool (400 m) - y as the original amount of water in the second pool (600 m) - a as the amount of water added to the first pool - b as the amount of water added to the second pool

Given: 1. The second pool was filled with 1.5 times less water than the first pool after the addition. 2. The first pool ended up with 100 m more water than before.

We can form the following equations based on the given information: 1. y - b = 1.5(x + a) (The second pool was filled with 1.5 times less water than the first pool after the addition) 2. x + a = 400 + 100 (The first pool ended up with 100 m more water than before)

Let's solve for a and b using these equations.

Solving for the Amount of Water Added to Each Pool

From the second equation, we can solve for a: a = 500 - x

Substitute this value of a into the first equation: y - b = 1.5(x + (500 - x)) y - b = 1.5(500) y - b = 750

Given that y = 600, we can solve for b: 600 - b = 750 b = 600 - 750 b = -150

This negative value for b indicates an error in the calculation. Let's re-evaluate the problem and the given information to ensure accuracy.