Question

На 1 стоянке было в 3 раза меньше автомашин чем на второй.После того как на первую стоянку приехало 18 машин,со 2 уехало 10,и на обеих стало поровну.Сколько машин было на каждой стоянке первоначальноПомогите:)

Answer 1

Было                                                                                                        стало
1 стоянка - х                                                                                   х+18
2 стоянка - х·3                                                                               х·3-10
1)х+18=х·3-10
х+18+10=3х
х+28=3х
х-3х=-28
-2х=-28
х=-28÷(-2)
х=14 на первой стоянке
2)14·3=42 на второй

Answer 2

Problem Analysis

We are given information about two parking lots. The first parking lot has three times fewer cars than the second parking lot. After 18 cars arrived at the first parking lot and 10 cars left, both parking lots had an equal number of cars. We need to determine the initial number of cars in each parking lot.

Solution

Let's assume the initial number of cars in the second parking lot is x. Since the first parking lot has three times fewer cars, the initial number of cars in the first parking lot would be x/3.

According to the given information, after 18 cars arrived at the first parking lot and 10 cars left, both parking lots had an equal number of cars. This can be expressed as:

(x/3 + 18) = (x - 10)

To solve this equation, we can simplify it:

x/3 + 18 = x - 10 x/3 - x = -10 - 18 (3x - x*3)/3 = -28 2x/3 = -28 2x = -28 * 3 2x = -84 x = -84/2 x = -42

Since the number of cars cannot be negative, we can conclude that there was an error in the given information or the problem statement. Please double-check the information provided.

If you have any further questions, please let me know.