
Решите систему неравенств 1/х<х х+2>=0 Заранее Спасибо!


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Solving the System of Inequalities
To solve the system of inequalities 1/x < x and x + 2 > 0, we will break it down into two separate inequalities and find the solution for each one.
# Inequality 1: 1/x < x
To solve the inequality 1/x < x, we can start by multiplying both sides of the inequality by x. However, since x can be positive or negative, we need to consider both cases separately.
Case 1: x > 0
If x > 0, we can multiply both sides of the inequality by x without changing the direction of the inequality:
1/x < x
Multiplying both sides by x:
1 < x^2
Taking the square root of both sides:
1 < x
So, for x > 0, the solution to the inequality 1/x < x is 1 < x.
Case 2: x < 0
If x < 0, we need to multiply both sides of the inequality by x, which reverses the direction of the inequality:
1/x < x
Multiplying both sides by x:
1 > x^2
Taking the square root of both sides:
1 > x
So, for x < 0, the solution to the inequality 1/x < x is x < 1.
# Inequality 2: x + 2 > 0
To solve the inequality x + 2 > 0, we can subtract 2 from both sides:
x > -2
So, the solution to the inequality x + 2 > 0 is x > -2.
# Combining the Solutions
Now that we have found the solutions for each inequality, we can combine them to find the overall solution for the system of inequalities.
For x > 0, the solution is 1 < x.
For x < 0, the solution is x < 1.
For x > -2, the solution is x > -2.
Therefore, the overall solution for the system of inequalities 1/x < x and x + 2 > 0 is:
x < 1 or x > -2.
Please note that the solution is expressed in interval notation.


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