Question

Расстояние между двумя городами равно 280км. Два автомобиля одновременно выехали из этих городов навстручу друг другу и встретились через 2 часа. Какова была скорость каждого автомобиля, если скорость первого была на 10км/ч больше второго?

Answer 1

2х+2(х+10)=280
2х+2х+20=280
4х=280-20
4х=260
х=65 (км/ч)-скорость 1 автомобиля.
65+10=75(км/ч)-скорость 2 автомобиля
Ответ  65 и 75

Answer 2

280:2=140 (км/ч) скорость сближения или сумма скоростей
(140-10):2=130:2=65 (км/ч) скорость второго
65+10=75 9км/ч) скорость первого
Ответ: скорость первого автомобиля 75 км/ч, а второго 65 км/ч

Answer 3

Problem Analysis

We are given that the distance between two cities is 280 km. Two cars simultaneously start from these cities towards each other and meet after 2 hours. We need to find the speed of each car, given that the speed of the first car is 10 km/h greater than the speed of the second car.

Solution

Let's assume the speed of the second car is x km/h. Then, the speed of the first car would be x + 10 km/h.

We can use the formula speed = distance / time to find the speeds of the cars.

The first car travels for 2 hours, so the distance it covers is 2 * (x + 10) km.

The second car also travels for 2 hours, so the distance it covers is 2 * x km.

Since the total distance covered by both cars is 280 km, we can write the equation:

(2 * (x + 10)) + (2 * x) = 280

Simplifying the equation:

2x + 20 + 2x = 280

4x + 20 = 280

4x = 260

x = 65

Therefore, the speed of the second car is 65 km/h and the speed of the first car is 75 km/h.

Answer

The speed of the first car is 75 km/h and the speed of the second car is 65 km/h.