Question

В двух корзинах 36 яблок .из первой корзины переложили во вторую 2 яблока после этого в первой корзине яблок стало 80% количества яблок второй корзины. Сколько яблок было в каждой корзине сначало?

Answer 1

Пусть х-во второй корзине
х+2 - во второй после перекладки яблок
(х+2) * 0,8-в первой
 х+2+0,8*(х+2)=36
х=18
в обеих корзинах по 18 яблок
для проверки
18-2=16-в первой
18+2=20-во второй
16=80% от 20

Answer 2

Problem Analysis

We are given two baskets with a total of 36 apples. Initially, we don't know the number of apples in each basket. We are then told that 2 apples are transferred from the first basket to the second basket. After this transfer, the number of apples in the first basket becomes 80% of the number of apples in the second basket. We need to determine the initial number of apples in each basket.

Solution

Let's assume that the initial number of apples in the first basket is x and the initial number of apples in the second basket is y.

According to the given information, we have the following equations:

1. x + y = 36 (since the total number of apples in both baskets is 36) 2. x - 2 = 0.8 * (y + 2) (since the number of apples in the first basket after transferring 2 apples is 80% of the number of apples in the second basket after receiving 2 apples)

We can solve this system of equations to find the values of x and y.

Solving the Equations

Let's solve the system of equations using substitution or elimination method.

From equation 1, we have:

x = 36 - y

Substituting this value of x in equation 2, we get:

36 - y - 2 = 0.8 * (y + 2)

Simplifying the equation:

34 - y = 0.8y + 1.6

Combining like terms:

1.8y = 32.4

Dividing both sides by 1.8:

y = 18

Substituting the value of y in equation 1, we get:

x = 36 - 18 = 18

Answer

Therefore, there were initially 18 apples in the first basket and 18 apples in the second basket.