
У прдавца 80 кг яблок.первый покупатель приобрел 10 кг яблок,а остальные а покупателей-по 6 кг
каждый.сколько яблок осталось у продовца? какие значение может принимать а?

Ответы на вопрос

2. Сколько число 6 можно повторить? Правильно 11 раз и это выйдет: 6 умножить на 11 = 66, а ведь больше нельзя, потому что должно выйти 70 кг, но у нас будет остаток. Ведь 70 - 66 = 4. У продавца осталось 4 яблока.



Problem Analysis
We are given that a seller has 80 kg of apples. The first buyer purchases 10 kg of apples, and the remaining buyers each purchase 6 kg of apples. We need to determine how many apples are left with the seller and the possible values that "a" can take.Solution
To find the number of apples left with the seller, we need to subtract the total amount of apples purchased from the initial quantity of 80 kg.The first buyer purchases 10 kg of apples, so we subtract 10 kg from the initial quantity.
The remaining buyers each purchase 6 kg of apples. To find the total amount purchased by the remaining buyers, we need to subtract the apples purchased by the first buyer (10 kg) from the initial quantity and then divide the remaining quantity by 6 kg.
Let's calculate the number of apples left with the seller:
1. Apples purchased by the first buyer: 10 kg 2. Remaining quantity after the first purchase: 80 kg - 10 kg = 70 kg 3. Apples purchased by the remaining buyers: 70 kg / 6 kg = 11.67 kg (rounded to the nearest whole number) 4. Total apples purchased: 10 kg + 11.67 kg = 21.67 kg (rounded to the nearest whole number) 5. Apples left with the seller: 80 kg - 21.67 kg = 58.33 kg (rounded to the nearest whole number)
Therefore, the seller has approximately 58 kg of apples left.
Now let's determine the possible values that "a" can take. Since "a" is not defined in the problem statement, we cannot determine its exact value. It could represent any variable or constant that is relevant to the problem. Without further information, we cannot provide specific values for "a".
Summary
The seller has approximately 58 kg of apples left. The possible values that "a" can take are not specified in the problem statement.

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