
Первый рабочий изготавливает 25 деталей в день а второй 29 первый заработал на 280 руб меньше
второго сколько они зарабатывают в месяц

Ответы на вопрос

280:4=70
280+70=350
350+280=630



Problem Analysis
We are given two workers who produce a certain number of parts per day and we need to calculate their monthly earnings. The first worker produces 25 parts per day and the second worker produces 29 parts per day. We also know that the first worker earns 280 rubles less than the second worker.Solution
To find the monthly earnings of the workers, we need to calculate the total number of parts produced by each worker in a month and then multiply it by their earnings per part.Let's calculate the monthly earnings for each worker step by step:
1. Calculate the total number of parts produced by the first worker in a month: - The first worker produces 25 parts per day. - There are typically 30 days in a month. - Therefore, the first worker produces 25 * 30 = 750 parts in a month.
2. Calculate the total number of parts produced by the second worker in a month: - The second worker produces 29 parts per day. - There are typically 30 days in a month. - Therefore, the second worker produces 29 * 30 = 870 parts in a month.
3. Calculate the earnings per part for each worker: - Let's assume the second worker earns x rubles per part. - The first worker earns 280 rubles less than the second worker, so their earnings per part would be (x - 280) rubles.
4. Calculate the monthly earnings for each worker: - The monthly earnings for the first worker would be the number of parts produced (750) multiplied by the earnings per part (x - 280). - The monthly earnings for the second worker would be the number of parts produced (870) multiplied by the earnings per part (x).
Therefore, the equation for the monthly earnings of the first worker would be: 750 * (x - 280) = ?
And the equation for the monthly earnings of the second worker would be: 870 * x = ?
To find the values of x and calculate the monthly earnings, we need more information. Unfortunately, the provided search results do not contain the necessary information to solve this problem.


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