Question

Из одной и той же исходной точки по кругу одновременно побежали дети. Миша пробежит один круг за 8 минут, Серёжа - за 3 минуты, а Нурлан - за 6 минут. Через сколько минут мальчики встретятся?

Answer 1

Найдем наименьшее общее кратное этих чисел, раскладываем на простые множители 8 (2 2 2) 3 (3) 6 (2 3) НОК =2*2*2*3 = 24
Значит, все прибегут в исходную точку одновременно через 24 минуты.
Самый быстрый сделает 8 кругов, средний - 4 круга, ну а ботаник - не спортсмен - 3 полн. круга.НОК(3,6,8)=24 минуты мальчики встретяться.

Answer 2

Problem Analysis

In this problem, we are given that three children, Misha, Sergey, and Nurlan, start running simultaneously from the same point on a circular track. We are also given the time it takes for each child to complete one lap around the track. We need to determine how many minutes it will take for the children to meet again at the starting point.

Solution

To solve this problem, we need to find the least common multiple (LCM) of the times it takes for each child to complete one lap around the track. The LCM will give us the time it takes for all three children to meet again at the starting point.

Let's calculate the LCM of the given times:

- Misha takes 8 minutes to complete one lap. - Sergey takes 3 minutes to complete one lap. - Nurlan takes 6 minutes to complete one lap.

The LCM of 8, 3, and 6 is 24. Therefore, it will take 24 minutes for all three children to meet again at the starting point.

Answer

The children will meet again at the starting point after 24 minutes.