Question

Периметр прямоугольника - 76 см. Найди его площадь, если ширина меньше длины на 4 см.

Answer 1

1)76:2=38 (см) длина и ширина

2)38-4=34 (см) длина и ширина без 4 см

3)34:2=17 (см) - ширина

4)17+4=21 (см) - длина

5) 21х17=357 (см квадр.)

Ответ: 357 см квадр.

 

Answer 2

Calculation of Rectangle's Area and Perimeter

To find the area and perimeter of a rectangle, we need to know the length and width of the rectangle. In this case, we are given that the perimeter of the rectangle is 76 cm and the width is 4 cm less than the length.

Let's denote the length of the rectangle as L and the width as W.

Finding the Perimeter

The perimeter of a rectangle is calculated by adding up all four sides of the rectangle. The formula for the perimeter of a rectangle is:

Perimeter = 2(L + W) Given that the perimeter of the rectangle is 76 cm, we can set up the equation:

76 = 2(L + W)

Since the width is 4 cm less than the length, we can express the width in terms of the length:

W = L - 4

Substituting this into the equation for the perimeter, we get:

76 = 2(L + (L - 4))

Simplifying the equation:

76 = 2(2L - 4)

76 = 4L - 8

4L = 84

L = 21

Now that we have found the length of the rectangle, we can substitute it back into the equation for the width:

W = L - 4 = 21 - 4 = 17

Therefore, the length of the rectangle is 21 cm and the width is 17 cm.

Finding the Area

The area of a rectangle is calculated by multiplying the length and width of the rectangle. The formula for the area of a rectangle is:

Area = L * W Substituting the values we found earlier:

Area = 21 * 17 = 357 cm^2

Therefore, the area of the rectangle is 357 square centimeters.

To summarize: - Length of the rectangle: 21 cm - Width of the rectangle: 17 cm - Perimeter of the rectangle: 76 cm - Area of the rectangle: 357 cm^2

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