Question

Из двух городов ,расстояние между которыми 782 км,навстречу друг другу выехали 2 поезда .Скорость одного 52км.ч ,второго 61км.ч,Проехав 416 км поезда встретились.На сколько часов один поезд вышел раньше другого

Answer 1

782-416=366км- прошел второй поезд до встрчи с первым366/61=6ч- время движения  второго поезда416/52=8ч- время движения первого поезда8-6=2ч- на столько раньше вышел второй))
Удачи с математикой!

Answer 2

Problem Analysis

We have two trains traveling towards each other from two cities that are 782 km apart. The first train has a speed of 52 km/h, and the second train has a speed of 61 km/h. After traveling 416 km, the trains meet. We need to determine how many hours one train left before the other.

Solution

To solve this problem, we can use the formula:

Time = Distance / Speed

Let's calculate the time it took for each train to travel the given distance.

For the first train: Time1 = Distance1 / Speed1 = 416 km / 52 km/h

For the second train: Time2 = Distance2 / Speed2 = (782 km - 416 km) / 61 km/h

Now, let's calculate the difference in time between the two trains:

Time Difference = Time1 - Time2

Calculation

Using the given values:

Time1 = 416 km / 52 km/h = 8 hours Time2 = (782 km - 416 km) / 61 km/h = 6 hours

Time Difference = Time1 - Time2 = 8 hours - 6 hours = 2 hours

Answer

Therefore, one train left 2 hours earlier than the other train.

Explanation

The first train traveled at a slower speed, so it took longer to cover the same distance as the second train. As a result, the first train had to leave earlier to meet the second train at the given distance. The time difference between the two trains is 2 hours.