Question

Срочно помогите решить задачу!!! На одной пасеке 56 ульев на другой 48. С первой пасеки собрали на 80 килограмм больше меда, чем со второй. Сколько меда собрали с каждой пасеки, если в каждом улике было одинаковое количество меда?

Answer 1

56-48=8 ульев
80:8=10 кг  мёда в каждом улье
56*10=560 кг мёда собрали на одной пасеке
48*10=480 кг мёда собрали с другой пасеки

Answer 2

Problem Analysis

To solve this problem, we need to determine how much honey was collected from each apiary given that one apiary had 56 hives and the other had 48 hives. We also know that the first apiary collected 80 kilograms more honey than the second apiary, and each hive had the same amount of honey.

Solution

Let's assume that each hive in both apiaries had x kilograms of honey.

The total amount of honey collected from the first apiary would be 56x kilograms, and the total amount of honey collected from the second apiary would be 48x kilograms.

According to the problem, the first apiary collected 80 kilograms more honey than the second apiary. Therefore, we can set up the following equation:

56x = 48x + 80

To solve for x, we can subtract 48x from both sides of the equation:

56x - 48x = 80

Simplifying the equation:

8x = 80

Dividing both sides of the equation by 8:

x = 10

Therefore, each hive had 10 kilograms of honey.

To find the total amount of honey collected from each apiary, we can substitute x = 10 back into the equations:

- The first apiary collected 56 * 10 = 560 kilograms of honey. - The second apiary collected 48 * 10 = 480 kilograms of honey.

Answer

Therefore, the first apiary collected 560 kilograms of honey, and the second apiary collected 480 kilograms of honey.