Question

Смешали два раствора. Масса первого раствора 2000 гр, соль составляет в ней 50%. Масса второго раствора 3,6 кг. Соль составляет в ней 1%. Найдите концентрацию смеси.

Answer 1

Общая масса воды (как вариант, может быть и др. Растворитель) 4564 гр. Соли - 1036 гр. Отсюда 1036*100/4564= 22.699 %

Answer 2

Calculation of the Concentration of the Mixture

To find the concentration of the mixture, we need to calculate the total amount of salt in the mixture and divide it by the total mass of the mixture.

Let's calculate the amount of salt in the first solution: - Mass of the first solution: 2000 grams - Salt concentration in the first solution: 50%

The amount of salt in the first solution can be calculated as follows: ``` Amount of salt in the first solution = Mass of the first solution * Salt concentration in the first solution = 2000 grams * 50% = 1000 grams ```

Now, let's calculate the amount of salt in the second solution: - Mass of the second solution: 3.6 kilograms - Salt concentration in the second solution: 1%

The amount of salt in the second solution can be calculated as follows: ``` Amount of salt in the second solution = Mass of the second solution * Salt concentration in the second solution = 3.6 kilograms * 1% = 36 grams ```

Next, we need to calculate the total amount of salt in the mixture: ``` Total amount of salt in the mixture = Amount of salt in the first solution + Amount of salt in the second solution = 1000 grams + 36 grams = 1036 grams ```

Finally, we can calculate the concentration of the mixture: ``` Concentration of the mixture = Total amount of salt in the mixture / Total mass of the mixture = 1036 grams / (2000 grams + 3.6 kilograms) = 1036 grams / 3600 grams ≈ 0.288 or 28.8% ```

Therefore, the concentration of the mixture is approximately 28.8%.