Question

Митя в 5 раз моложе бабушки , а отец в 3 раза старше Мити.Всем вместе 108 лет. Сколько лет каждому? Задачу надо по действиям или по частям. Спасибо

Answer 1

1) 108:3=36(лет) папе 2) 36:3=12(лет) Мите 3) 12×5=60(лет) бабушке Проверка: 36+12+60=108 Ответ:папе

Answer 2

Problem Analysis

We are given the following information: - Mitya is 5 times younger than his grandmother. - Mitya's father is 3 times older than Mitya. - The sum of their ages is 108 years.

We need to determine the age of each person.

Solution

Let's assume Mitya's age is x years. Based on the given information, we can determine the following equations:

1. Mitya's age: x 2. Grandmother's age: 5x 3. Father's age: 3x

The sum of their ages is 108 years, so we can write the equation:

x + 5x + 3x = 108

Simplifying the equation:

9x = 108

Dividing both sides by 9:

x = 12

Now we can substitute the value of x back into the equations to find the ages of each person:

- Mitya's age: x = 12 years - Grandmother's age: 5x = 5 * 12 = 60 years - Father's age: 3x = 3 * 12 = 36 years

Therefore, Mitya is 12 years old, his grandmother is 60 years old, and his father is 36 years old.

Answer

Mitya is 12 years old, his grandmother is 60 years old, and his father is 36 years old.