Question

Помогите решить задачу! Квадрат и прямоугольник имеют одинаковый периметр-36 см Площадь какой фигуры больше, если длина прямоугольника 10 см?

Answer 1

1)36-10*2=8(см)
2)36:4=9(см)
3)8*10=80(см)
4)9*9=81(см)

Answer 2

Problem Analysis

We are given that a square and a rectangle have the same perimeter of 36 cm. The length of the rectangle is given as 10 cm. We need to determine which figure has a greater area.

Solution

To solve this problem, we need to compare the areas of the square and the rectangle.

Let's start by finding the side length of the square. Since the perimeter of the square is 36 cm, we can divide it by 4 to find the length of each side.

The side length of the square is 9 cm.

Now, we can calculate the area of the square by squaring the side length:

Area of the square = side length^2 = 9 cm^2.

Next, let's calculate the area of the rectangle. We are given that the length of the rectangle is 10 cm. To find the width, we can use the formula for the perimeter of a rectangle:

Perimeter of a rectangle = 2(length + width).

Since the perimeter of the rectangle is 36 cm and the length is 10 cm, we can substitute these values into the formula and solve for the width:

**36 cm = 2(10 cm +