Question

Какова масса нефти поместится в цистерну, которая имеет форму цилиндра, если внутренний диаметр цистерны равен 12 м., высота 10 м., плотность нефти 0,8 г./см. куб.

Answer 1

Объём цистерны (цилиндр)
$V=\pi\frac{d^2}4h=3,14\cdot\frac{144}4\cdot10=1130,4$ куб.м.
Масса нефти $m=\rho\cdot V=0,8\cdot1130,4=904,32$ тонны.

Answer 2

Calculating the Volume of the Cylinder:

To calculate the volume of the cylinder, we can use the formula for the volume of a cylinder, which is given by:

V = πr^2h

Where: - V is the volume - π is a constant approximately equal to 3.14159 - r is the radius of the cylinder - h is the height of the cylinder

Given that the internal diameter of the cylinder is 12 m, we can calculate the radius using the formula:

r = d/2

Where: - d is the diameter

Substituting the values, we get: r = 12/2 = 6 m

Now, we can calculate the volume using the formula for the volume of a cylinder.

Calculating the Mass of the Oil:

The mass of the oil can be calculated using the formula:

m = ρV

Where: - m is the mass - ρ is the density - V is the volume

Given that the density of the oil is 0.8 g/cm^3, we can convert the volume from cubic meters to cubic centimeters and then calculate the mass.

Calculation:

V = πr^2h V = 3.14159 * 6^2 * 10 V = 3.14159 * 36 * 10 V = 1130.9734 m^3

m = ρV m = 0.8 * 1130.9734 * 1000000 m = 904778.72 kg

Therefore, the mass of the oil that can be accommodated in the cylinder is approximately 904778.72 kg.

Answer 3

Для решения данной задачи необходимо сначала найти объем цистерны, а затем умножить его