Question

(На пропорции) Томас за 3 дня продал 180 сумок. В 1Вый день треть часть от 2ого дня продаж, а в 3 наполовину от 1ого дня продаж. Сколько сумок он продавал за каждый день

Answer 1

Х+1/3Х+1/2×1/3Х=180 1 1/3Х + 1/6 Х= 180
1 1/2Х=180
Х= 180/1 ÷ 1 1/2
Х= 180/1 × 2/3
Х= 360/3
Х=120
120- 2 день
40- 1 день
20 - 3 день

Answer 2

Problem Analysis

We are given that Thomas sold 180 bags in 3 days. On the first day, he sold one-third of the sales from the second day, and on the third day, he sold half of the sales from the first day. We need to determine how many bags he sold each day.

Solution

Let's assume that Thomas sold x bags on the first day, y bags on the second day, and z bags on the third day.

From the given information, we can write the following equations:

1. x + y + z = 180 (total bags sold in 3 days) 2. x = (1/3) * y (one-third of the sales from the second day) 3. z = (1/2) * x (half of the sales from the first day)

We can solve these equations to find the values of x, y, and z.

Substituting equation 2 into equation 3, we get:

z = (1/2) * ((1/3) * y) z = (1/6) * y

Substituting the value of z into equation 1, we get:

x + y + (1/6) * y = 180 x + (7/6) * y = 180

To eliminate the fraction, we can multiply equation 2 by 6:

6x = 2y

Substituting the value of 6x from equation 2 into equation 1, we get:

2y + (7/6) * y = 180 (12/6)y + (7/6)y = 180 (19/6)y = 180

Solving for y:

y = (180 * 6) / 19 y ≈ 56.842

Substituting the value of y into equation 2, we get:

x = (1/3) * 56.842 x ≈ 18.947

Substituting the value of x into equation 3, we get:

z = (1/2) * 18.947 z ≈ 9.474

Therefore, Thomas sold approximately 18.947 bags on the first day, 56.842 bags on the second day, and 9.474 bags on the third day.

Answer

Thomas sold approximately 18.947 bags on the first day, 56.842 bags on the second day, and 9.474 bags on the third day.